(d³-d²-d)+(c³+c²+c)-(a³+a²-a)-(b³-b²-b)
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Answer:
If a + b + c = 1 a² + b² + c² = 2 a³ + b³ + c³ = 3
then what is the value of a⁴ + b⁴ + c⁴
Using the identity,
a4+b4+c4=
(a2+b2+c2)22
+(4)(a+b+c)(a3+b3+c3)3
+(a+b+c)46
−(a+b+c)2(a2+b2+c2)
for this problem,
a4+b4+c4=(2)22+(4)(1)(3)3+(1)46−(1)2(2)=256
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