Question

डांगी रेलवे बोर्ड भिवानी​

Answer 1

Answer:

check your equestrianL.C.M. of 8, 15 and 20 is 120.

Prime factors of 120 = 2 x 2 x 2 x 3 x 5

Here, prime factors 2, 3 and 5 have no pair. Therefore 120 must be multiplied by 2 x 3 x 5 to make it a perfect square.

\therefore120\times2\times3\times5=3600∴120×2×3×5=3600

Hence, the smallest square number which is divisible by 8, 15 and 20 is 3600.