डिसटीब्यूटर फॉर बुक्स इक्वली अमोंग 8 क्लासेस हाउ मेनी बुक्स विल ईट क्लास गेट
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Class 11
>>Applied Mathematics
>>Circles
>>Circles
>>Find the equation of the ci...
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Find the equation of the circle with radius 5 whose centre lies on x-axis and passes through the point (2,3)
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Given a circle of radius r=5
Given center lies on x-axis.
So, let the center be (h,0)
Equation of circle is
(x−h)
2
+y
2
=25 ....(1)
Since, it passes through (2,3)
⇒(2−h)
2
+3
2
=25
⇒(2−h)
2
=16
⇒2−h=±4
⇒h=−2,h=6
When h=−2, the equation of circle is
(x+2)
2
+y
2
=25
⇒x
2
+4x+4+y
2
=25
⇒x
2
+y
2
+4x−21=0
When h=6, the equation of circle is
(x−6)
2
+y
2
=25
⇒x
2
−12x+36+y
2
=25
⇒x
2
+y
2
−12x+11=0
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