Question

da. There unbiased coins are tossed together. Find the probability of getting 1 all neads 2 two heads 3 at least two heads 4 at most two heads ​

Answer 1

Answer:

Hit The Thanks Button!

Step-by-step explanation:

Three unbiased coins are tossed together.

 Sample space, S

 = {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}

 Number of events, n(S) = 8

i)

For getting one head, we will have the event space,

S₁ = {TTH, THT, HTT}

Number of events, n(S₁) = 3

Thus, the probability of getting one head

P(S₁) = 3/8

ii)

For getting two heads, we will have the event space,

S₂ = {HHT, HTH, THH}

Number of events, n(S₂) = 3

Thus, the probability of getting two heads

P(S₂) =  3/8

iii)

For getting all heads, we will have the sample space,

S₃ = {HHH}

Number of events, n(S₃) = 1

Thus, the probability of getting all heads

P(S₃) =  1/8

 

iv)

For getting at least two heads, we will have the sample space,

S₄ = {HHH, HHT, HTH, THH}

Number of events, n(S₄) = 4

Thus, the probability of at least two heads

P(S₄) = 1/2