Daily packet expenses in Rupees of 80 students in school are given in the table below
Expenses no. of students
0-5 5
5-10 15
10-15 20
15-20 10
20-25 10
25-30. 15
30-35 5
draw a less than and more than ogive on the same craft and hence find the median of the given frequency distribution also verify median formula
Answers
Given : Daily packet expenses in Rupees of 80 students in school
To find : draw a less than and more than ogive and find median
Solution:
Expenses f Cf Less than Cf More than
0 - 5 5 5 80
5 - 10 15 20 75
10 - 15 20 40 60
15 - 20 10 50 40
20 - 25 10 60 30
25 - 30 15 75 20
30 - 35 5 80 5
Median = 10 + 5 * ( 40 - 20)/20 = 15
Or
Median = 15 + 5* ( 40 - 40)/10 = 15
Same as from graph Median = 15 ( intersection of more than & less than ogive)
Less than ogive
The points with the upper limits of the class are plotted on x axis and the corresponding less than cumulative frequencies on y axis.
The points are joined by free hand smooth curve to give less than cumulative frequency curve or the less than Ogive
More than ogive
The points with the Lower limits of the class are plotted on x axis and the corresponding more than cumulative frequencies on y axis.
The points are joined by free hand smooth curve to give more than cumulative frequency curve or the More than Ogive
Learn More:
if the less than type ogive and more than type ogive intersect each ...
https://brainly.in/question/17495794
what type of ogive do we call a graph which has been drawn ...
https://brainly.in/question/13741836
for the distribution with100 observation ,the less then ogive and ...
https://brainly.in/question/15922849
