Physics, asked by monesh69, 4 hours ago

Daksha is in the centre of the city and facing
towards North direction. Towards her right is a
market at 407 m, towards West 779 m away is
the office, 241 m South of the market is the
medical shop and 985 m North from the market
is her friend's house.
If she first went to the office and next to the
market, then to medical shop and later to her
friend's house and walked in a straight line,
then how much is the total distance covered by
her?

Answers

Answered by nagendracktd
0

Answer:

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Answered by qwvilla
0

ANSWER:

The total distance travelled is 3km 432m.

Given :

Distance of market = 407 m towards East

Distance of office = 779 m towards West

Distance of medical shop = 241m towards South of the market

Distance of friend's house = 985m towards North of the market

To find :

Total distance covered by Daksha

Solution :

As she first went to the office, hence , the distance = 779m

Then she moved to the market, as market is towards the east, hence distance travelled by her to reach market = Distance back from office + Distance of market

= 779 + 407

= 1186 m

Then she moved to the medical shop which is towards South of market , hence distance travelled = 241m

Lastly she moved to friend's house towards North of market , hence distance travelled = Distance to travel back from medical shop + Distance to travel to friend's house

= 241 + 985

= 1226m

Therefore the total distance travelled by her = (779 + 1186 + 241 + 1226 )m

= 3432m

= 3km 432m

Hence, the total distance travelled is 3km 432m

#SPJ2

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