Math, asked by prernavlko8624, 1 year ago

Daku and tamatar can do a piece of work in 70 and 60 days respectively. They began the work together, but daku leaves after some days and tamatar finished the remaining work in 47 days. After how many days did daku leave?

Answers

Answered by rathibhagwati3
8

Answer:


Step-by-step explanation:


Attachments:
Answered by pinquancaro
10

Answer:

In 7 days Daku leave.

Step-by-step explanation:

Given : Daku and tamatar can do a piece of work in 70 and 60 days respectively. They began the work together, but daku leaves after some days and tamatar finished the remaining work in 47 days.

To find : After how many days did daku leave?    

Solution :

Let the Daku be 'x' and tamatar be 'y'.

Work done by Daku is x=\frac{1}{70}

Work done by Tamatar is y=\frac{1}{60}

Productivity of both x and y is

x+y=\frac{1}{70}+\frac{1}{60}

x+y=\frac{60+70}{4200}

x+y=\frac{130}{4200}

x+y=\frac{13}{420}

Daku leaves after some days and Tamatar finished the remaining work in 47 days.

Amount of work done by Tamatar is y=47\times\frac{1}{60}=\frac{47}{60}

Remaining work is 1-\frac{47}{60}=\frac{60-47}{60}=\frac{13}{60}

Work done together is \frac{13}{60}

Number of days they worked together is

n=\frac{\frac{13}{60}}{\frac{13}{420}}

n=\frac{13}{60}\times \frac{420}{13}

n=7

Therefore, In 7 days Daku leave.

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