Question

DAL 2. 3. Eight times of a number reduced by IU 15 Equur Find the number A number consists of two digits whose sum is 9. If 27 is subtracted from the number its digits are reversed. Find the number. her is divided into two parts such that one part is 10 more than the other. If the two Solutio parts.​

Answer 1

Answer:

Let one digit of the number be x , then its ten  digits digits will be (8−x) . 

So , given number =10(8−x)+x 

                                 =80−10x+x 

                              =80−9x

Now if digits are reversed  , then Number obtained  

                                 =10x+(8−x)

                                 =10x+8−x

                                 =9x+8

According to question 

        (80−9x)+18=9x+8

         98−9x=9x+8 

         90=18x

           x=5

⇒ given number  =80−9x

                                          =80−9×5      

                                          =80−45 

                                          =35         

                                        

∴ the number is 35