Question

Dale Page No O. NO 3] To check the correctness of phiysteed equation 3] v2 =42+2 as by using dimensional analysis, ​

Answer 1

Answer:

Given equation:

• v² = u² + 2as

Physical Quantities:

• v = final velocity
• u = initial velocity
• a = acceleration
• s = distance

Dimensions:

$\footnotesize\:\longrightarrow \text{ v = [LT}^{-1}]$

$\footnotesize\:\longrightarrow \text{ u= [LT}^{-1}]$

$\footnotesize\:\longrightarrow \text{ a = [LT}^{-2}]$

$\footnotesize\:\longrightarrow \text{ s= [L]}$

Procedure:

• LHS:

$\footnotesize\:\longrightarrow v^2 = [LT^{-1}]^2 = [L^2T^{-2}]$

• RHS:

$\footnotesize\:\longrightarrow u^2= [LT^{-1}] =[L^2T^{-2}]$

Also,

$\footnotesize\:\longrightarrow \text{ as = [LT}^{-2}] [L] = [L^{2} T^{-2}]$

LHS = RHS, Therefore given equation is dimensionally correct.