Math, asked by hasnainhasu8095, 4 months ago

daljeet is a money lender.Pritish borrowed money from him at 5half %p.a.for 135 days to be able to start with his own cokking classes.If he paid an interset of ₹500,how much money did he borrow? (hint:there are 365 days in a year.So, time period(T)will be 135/365​

Answers

Answered by herafatima054
0

answer

Here rate of interest = r=

5\frac{1}{2}\%=\frac{11}{2}\%521%=211%

Time period = t =

\frac{135}{365}365135

Interest = I = 500.

To find: The principal amount = p.

Now we know that the equation for the interest is given as:

I=\frac{p\times r\times t}{100}I=100p×r×t

So, now on putting the values in the above equation we have:

\begin{gathered}\begin{gathered} 500=\frac{p\times\frac{11}{2}\times\frac{135}{365}}{100} \\ p=500\times\frac{100}{\frac{11}{2}\times\frac{135}{365}}=50000\times2\times\frac{365}{11\times135}=24579.12 \end{gathered}\end{gathered}500=100p×211×365135p=500×211×365135100=50000×2×11×135365=24579.12

So, the borrowed amount is 24579.12.

*hope this will help you *

Answered by nhavipriyanshu
0

Answer:

₹ 24,579.12.

Step-by-step explanation:

Given: Rate of interest (R) =5 1/2 =11/2% per annum;

Time (T) =135 days =135/365 year; interest paid

=₹500

Asked: Amount of money borrowed by Pritish (P)

We know that S.I.=P×R×T/ 100

= 500=P×11/2 ×1/100×135/365

= Principal (P)=500×2×100×365/11×1×135

= Principal(P) =24,579.12

Hence, the money borrowed by Pritish is ₹24.579.12.

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