Dalton law of partial pressure derivation
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According to this Law " the pressure of a mixture of unreactive gases is equal to the sum of partial pressure of all gases present in the mixture " .
The pressure exerted by individual gas in the mixture is called it's partial pressure.
Pg= ng ×P /nt --------->eq = 1
where
pg = partial pressure of gas
ng = number of moles of gas
nt = total moles in the mixture .
P = total pressure of the mixture.
consider a mixture of four unreactive gases
example:- A ,B, C & D applying Pa ,Pb ,PC,& Pd partial pressure respectively then using the law ,
we have
P = Pa ,Pb ,Pc & Pd -------------->eq =2
Thus law is applicable in the preparation of gases over water .
P dry gas=P moist gas -- P water vapours-->eq=3
Example :- mixture of 8 gases (air )
I Hope it will help you.
if helpful then mark as brainlist answer
The pressure exerted by individual gas in the mixture is called it's partial pressure.
Pg= ng ×P /nt --------->eq = 1
where
pg = partial pressure of gas
ng = number of moles of gas
nt = total moles in the mixture .
P = total pressure of the mixture.
consider a mixture of four unreactive gases
example:- A ,B, C & D applying Pa ,Pb ,PC,& Pd partial pressure respectively then using the law ,
we have
P = Pa ,Pb ,Pc & Pd -------------->eq =2
Thus law is applicable in the preparation of gases over water .
P dry gas=P moist gas -- P water vapours-->eq=3
Example :- mixture of 8 gases (air )
I Hope it will help you.
if helpful then mark as brainlist answer
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