Damoh present age of O2 in a mixture of 7 grams of N2 and 8 grams of O2 is
Answers
Answered by
1
Answer:
The molar percentage of O2 in the mixture is 50%.
Explanation:
Given
Mass of N2 = 7 grams
mass of O2 = 8 grams
Molar Percentage of O2 = ??
Solution
As we know that, In order to find molar percentage first we have to convert given mass into number of moles,
therefore,
No. of Moles = Given mass/ Molecular mass
Molecular mass of O2 = 16 g/ mol
Molecular mass of N2 = 14 g/ mol
For N2
No. of moles of N2 = 7/ 14
No. of moles of N2 = 0.5 moles
while, for O2
No. of moles of O2 = 8/ 16
No. of moles of O2 = 0.5 moles
Formula for molecular percentage can be written as:
Molecular percentage of O2 = (no. of moles of O2/ total no. of moles of mixture) X 100
Molecular percentage of O2 = (0.5/ 1) X 100
Molecular percentage of O2 = 50 %
Explanation:
Similar questions