Question

Dande are points on the sides ca and CB
respectively of a triangle ABC right angled at 6 c.
prove that AE²+ B0²=AB²+ DEZ.​

Answer 1

Answer:

Given:- △ABC, right angled at C.

Two points D and E are on the sides AC and AB.

To prove:- AE2+BD2=AB2+DE2

Construction:- Join the point D with B and Eand point E with A.

Proof:-

Using pythagoras theorem,

Hypotenuse2=Perpendicular2+Base2

In △ACE,

AE2=AC2+CE2.....(1)

In △BCD,

BD2=DC2+BC2.....(2)

In △ABC,

AB2=AC2+BC2.....(3)

In △DCE,

DE2=DC2+CE2.....(4)

Now,

AE2+BD2=AB2+DE2

AC2+CE2+DC2+B

Step-by-step explanation:

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Answer 2

ur answer is attached, hope it's help u.....