Question

Danial is painting the walls and ceiling of a cuboidal hall with length and breadth and height 15m ,10m and 7m respectively . Find each can of paint 100msquare of area is painted . How many cans of paint will she need to paint the room

Answer 1

Heya,

Given:-
Length = 15m
Breadth = 10m
Height = 7m

To find:-
How many cans of paint will be required to paint the hall.

Solution:-

Area = 2h (l + b) + lb [because Daniel paint for 4 walls and the ceiling where the floor isn't painted]

So,
Area = 2 × 7 (15 + 10) + (15 × 10)
Area = 14 (25) + (150)
Area = 350 + 150
Area = 500m^2

To find the cans required,
No of required cans = Area of the hall/100m^2
No of required cans = 500/100
No of required cans = 5 cans

Hope my answer helps you :)

Regards,
Shobana

Answer 2

Hello,

given that:
b(length)=15 m,
h(breadth)=10m,
H(height)=7 m
we calculate the area of celling:
A₁=b×h=15×10=150 m²
we calculate the area of the wall:
A₂=2(bH+hH)=2×(15×7+10×7)=2×(105+70)=2×175=350 m²
we calculate the area of the hall to be painted:
A=A₁+A₂=150+350=  500 m²

It is given that 100m² area can be painted from each can.
we calculate the number of cans required to paint an area A:
n=A:100=500:100=5

Hence, 5 cans are required to paint the walls and the ceiling of the cuboidal hall.

bye :-)