Question

Daniel is painting the wall and ceiling of a cuboidal hall with Length breadth and height of 15m 10m and 7m respectively from each can of.100m^2 of area is painted how many cans of paint will he need to paint to entire room​

Answer 1

Answer:

Step-by-step explanation:

T. S. A. OF CUBOID - N(VOLUME OF CANS)

HERE N IS THE NO. OF CANS.

YOU ARE GOING TO DO BOARDS SO SOLVE IT BRO.

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Answer 2

Answer:

Step-by-step explanation:

Given;

Length of wall (l)= 15 m, Breadth of wall  (b)= 10 m Height of wall (h) = 7 m

Total area to be painted= area of 4 walls + area of ceiling

= 2(l+b)h + lb

= 2(15+10)7 + 15×10

= 2×25×7+ 150

=50× 7+150= 350+ 150=500

Total area to be painted=500m²

Given 100m² area can be painted from each can.

 Number of cans Required=

Area of hall/ area of 1 can

= 500/100= 5

Hence, 5 cans are required to paint the room.