Question

Daniel is painting the walls and ceiling of a cuboidal hall with length, breath and height of 15m, 10m and 7m respectively. From each can of hundred square of area is painted.
How many cans of paint will she need to paint the room?​

Answer 1

El❤

L:- 15m

B:- 10m

h:- 7m.

Area of painted :- Area of 4 walls+Area of ceiling.

______________ 2h(l+b)+l×b

_______________2×7(15+10)+15×10

_______________14(25)+150

_______________350+150

_______________500m^2.

So, Total no of cans:- 500÷100= 5cans.

Hope it help's uh✌...

Answer 2

$\huge\tt\green{SoLutiOn:-}$

Given that

★ length = 15m

★ Breadth = 10m

★ Height = 7m

Then according to questions :-

Total area to be painted = 2(l + b)× h + lb

= 2 × (15 + 10) × 7 + 15 × 10

= 2 × 25 × 7 + 150

= 50 × 7 + 150

= 350 + 150

= 500m²

Now ,

Number of paint cans required

= $\frac{500{m}^{2}}{100{m}^{2}}$

= 5cans

Therefore , 5 cans are required to paint.