Question

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint 100 m2 of the area is painted. How many cans of paint will she need to paint the room?​

Answer 1

Question :-

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint 100 ${m}^{2}$ of the area is painted. How many cans of paint will she need to paint the room?

Given :-

• Length = 15m

• breadth = 10m

• height = 7m

To find :-

• How many cans of paint will she need to paint the room?

Solution :-

➠ $Total \: surface \: area \: – Area \: of \: base$

➠ $2 [lb + bh + hl] – lb$

➠ $2 [15 × 10 + 10 × 7 + 7 × 15] – 15 × 10$

➠ $2[150 + 70 + 105] – 150$

➠ $2 [325] – 150$

➠ $500 {m}^{2}$

___________

$Area \: of \: the \: paint \: in \: one \: can = 100 {m}^{2}$

___________

${Number \:of \:cans\: required \:= \dfrac{500}{100}}$

= 5 cans.

Answer 2

$\huge\mathfrak {Answer: }$

Area to be painted = area of the walls + area of ceiling

=2(hl+hb)+lb

=[2×(7×15+7×10)+(15×10)]=500 sq m

No. of cans required = 500/100

=5

Hence, 5 cans are required to paint the walls and the ceiling of the cuboidal hall.