Question

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15m, 10m and 7m respectively. from each of paint 100m^ of area is painted.
how to make cans of paint will she needed to make room?

Answer 1

Area of All walls, ceilings and floor or Tsa = 2(lb + lh + bh)
= 2(15 x 10 + 15 x 7 + 10 x 7)
= 2(150 + 105 + 70)
= 2 x 325 = 650
Area of Floor = 15 x 10 = 150
Hence, Painted Area =650-150=500
As, one can of paint is enough for 100 sq m
So, 500/100 =
5Cans are needed
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Answer 2

$hello$

$here \: is \: your \: answer$

$area \: of \: hall \: to \: be \: painted =2(l \times b + b \times h + l \times b) - l \times b$

$= 2(15 \times 10 + 10 \times 7 + 7 \times 15) - 15 \times 10$

$2(150 + 70 + 105) - 150$

$650 - 150$

$= 500 {m}^{2}$

$no. \: of \: cans = \frac{total \: area}{area \: painted \: 1 \: can}$

$= \frac{500}{100}$

$5 \: cans$

$\huge \: 5 \: cans \: are \: required \: to \: paint \: the \: wall$

$thanks$

$hope \: you \: like \: my \: answer$