Question

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m , 10 m and 7 m respectively. From each can of paint 100 sq metre of area is painted. How many cans of paint will she need to paint the room ?

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Answer 1

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Area to be painted = [Area of 4-walls] + Area of ceiling

= 2[Perimeter x Height] + l x b

= 2[(15+10) x 7] + 15 x 10 m2

= 2[25 x 7] + 150 m2

= 2 x 175 + 150 m2

= 350 + 150 m2

= 500 m2

Since 1 can of paint covers 100 m2 area.

∴ Number of cans required = 500/100

= 5

Answer 2

Explanation:

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