Question

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m , 10 m and 7 m respectively. From each can of paint 100 sq metre of area is painted. How many cans of paint will she need to paint the room ?

Please give good answers only..

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Answer 1

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Solution :-

→Area of wall to painted.

→Area of 4 walls + Area of top

→2h(l + b) + (l × b)

→2 h (15 + 10) + (15 × 10)

→14 × 25 + 150

→350 + 150

→500m^2

No of cans required = Area of wall / Area of covered by 1 can

→500 / 100

=> 5

Answer 2

Answer:

↦Area of wall to painted.

↦Area of 4 walls + Area of top

↦2h(l + b) + (l × b)

↦2 h (15 + 10) + (15 × 10)

↦14 × 25 + 150

↦350 + 150

↦500m²

No of cans required = Area of wall / Area of covered by 1 can

↦500 / 100

⇒ 5

Thanks!!