Question

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15m, 10m and 7m respectively. for each can of paint 100 m^2 of area is painted how many cans of paint will be needed to paint the entire room.​

Answer 1

${\huge{\boxed{\underline{\sf{Given:-}}}}}$

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15m, 10m and 7m respectively. for each can of paint 100 m^2 of area is painted

${\huge{\boxed{\underline{\sf{To\;Find:-}}}}}$

how many cans of paint will be needed to paint the entire room.​

${\huge{\boxed{\underline{\sf{Solution :-}}}}}$

We know that

Area of four walls = 2(l + b) × h

Area of rectangle = l × b

Area of room = Area of four walls + Area of rectangle

Area of room = 2(l + b) × h + l × b

Area of room = 2(10 + 15) × 7 + 15 × 10

Area of room = 2(25) × 7 + 150

Area of room = 50 × 7 + 150

Area of room = 350 + 150

Area of room = 500 m²

Now

1 can of paint = 100 m²

1 m² can be painted by = 1/100 can

Total cans required = 1/100 × 500

Total cans required = 500/100

Total cans required = 5/1

Total cans required = 5 cans