Question

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint 100 m² of area is painted. How many cans of paint will she need to paint the room?
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Answer 1

As per the data given in the question,

In the above question, it is given that,

The length of a cuboidal hall is =15m

The breadth of a cuboidal hall is =10m

The height of a cuboidal hall is =7m

Each can of paint 100 m² of the area is painted.

We have to find how many cans of paint will she need to paint the room.

$\begin{aligned}\text { Area to be painted } &=[\text { Area of } 4 \text {-walls }]+\text { Area of ceiling } \\&=2[\text { Perimeter } \times \text { Height }]+1 \times b \\&=2[(15+10) \times 7]+15 \times 10 \mathrm{~m}^{2} \\&=2[25 \times 7]+150 \mathrm{~m}^{2} \\&=2 \times 175+150 \mathrm{~m}^{2} \\=& 350+150 \mathrm{~m}^{2} \\=& 500 \mathrm{~m}^{2}\end{aligned}$

one can of paint 100 m² of the area.

Therefore the number of cans required$=\frac{500}{100}\\=5$

Hence 5 cans of paint are required to paint the room.

Answer 2

5 cans

Given, Daniel is painting the walls and ceiling of a cuboidal hall, the length of cuboidal hall is 15m, breadth of cuboidal hall is 10m and height of cuboidal hall is 7m. can. Hence, we got that Daniel will need 5 cans to paint the room.

Hei can give me some point pls