Math, asked by prasadguturi756, 1 year ago

Daniel is painting the walls and ceiling of a cuboidal hall with length,breadth,height of 15cm,10m,and 7m respectively . From each can of paint,100m3 of area cv painted. How many cans of paints will he need to paint the room?

indu1237493: Hey mate is it 15 cm or 15m ????

Answers

Answered by memustafabanday

Answer:

Step-by-step explanation:

Total surface area of cuboid=2×(lb+bh+lh)

2×(15×10+10×7+15×7)-lb(because he is not painting base of the room)

=325 m2

FRom each can he can paint=100m2

So,325/100

=3.5 cans.

To paint 325 m2 he needed 3 and half cans..

Note area is always in m2 not in m3

indu1237493: Hey mate tell me in question it 15 cm then how will u take it as 15m

memustafabanday: Sorry 15 cm.

memustafabanday: Is it ok..

indu1237493: But u should take it as 15/100m ....right????

memustafabanday: there are many methods to solve this sum...

memustafabanday: haan if u want to convert it into metres then u have to divide it by 100

memustafabanday: ok...___$$

Answered by moonstar16098

Surface area of a cuboidal hall without bottom = Total surface area – Area of base

= 2 [lb + bh + hl] – lb

= 2 [15 × 10 + 10 × 7 + 7 × 15] – 15 × 10

= 2[150 + 70 + 105] – 150

= 2 [325] – 150

= 650 – 150

= 500 m2

Area of the paint in one can = 100 m2

Number of cans required = 500100 = 5 cans.

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