Question

Daniel is painting the walls and ceilings of a cuboidal hall with Length breadth and height of 15m,10m and 7m respectively.From each can of paint, 100 sq.m. of area is painted.How many cans of paint will he need to paint the entire room?

Answer 1

Answer:

The answer is

Step-by-step explanation:

Let the length be l, breadth be b and height be h of the cuboidal hall then l=15m, b=10m, h=7m

Since the hall is cuboidal in shape so, the area painted by Daniel of hall= Area of the cuboid, which is equal to the area of four walls + area of ceiling

Then the area painted by Daniel of hall 

= 2(l+b)h + lb= 2(l+b)h + lb

substituting the values of the length l breadth b and height h of the cuboidal hall in the above formula we get,

area painted by Daniel of hall 

= 2(15 + 10)7 + (15)(10)= 2(15 + 10)7 + (15)(10)

⇒⇒

area painted by Daniel of hall 

=350 + 150=350 + 150

⇒⇒

area painted by Daniel of hall 

=500m2=500m2

Now we are given that from each can of paint, 100m of area is painted implies 100m square of area is painted by 1 can

⇒⇒

1 m square of area is painted by 

11001100

can

Therefore, 500 m square of area is painted by Daniel in 

500100=5500100=5

Hence, we got that Daniel will need 5 cans to paint the roo