Dar
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. If HCF Ca, b = 12 Es axb=1800,
- I and Its 2 cm.
2. The LCM & HCP of two Numbers
is 180 and 6 Respectively . If
One of the number is 30.
- find the other number.
Answers
Answered by
2
Step-by-step explanation:
2 sol:
Given that,
LCM of two numbers = 180
HCF of two numbers = 6
One of the number = 30
Let the other number be x
Now,
Product of two numbers = LCM x HCF
30 × X = 180 × 6
X = 1080 / 30
X = 36
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