Question

Dare to solve!! Brainliest​

Answer 1

Let x^a=y^b=z^c=k

then, x=k^1/a, y=k^1/b, z=k^1/c

Given- y=xz

So, k^1/b=k^1/a*k^1/B

Equating powers, we get

1/b=1/a+1/c

So, 1/a+1/b+1/c = 1/b+1/b = 2/b

So, (c) is the correct option

Pls mark as Brainliest!!

Answer 2

Here's your answer. Option c is correct