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∠RST+∠SRU=180∘
(Sum of the consecutive interior angles on the same side of the transversal is 180∘)
⇒130∘+∠SRU=180∘
⇒∠SRU=180∘−130∘=50∘ ………(i)
∠QRU=∠PQR=110∘ (alternate interior angles)
⇒∠QRS+∠SRU=110∘
⇒∠QRS+50∘=110∘ (using (i))
⇒∠QRS=110∘−50∘=60∘
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