Dase is of length 25 cm and the corresponding
In a parallelogram ABCD, AB = 18 cm, BC = 12 cm. AE I DC, AF 1 BC and if
2
Find the area of a rhombus whose one side is 13 cm and the altitude is 10 cm.
AE = 6.4 cm, find the length of AF.
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Step-by-step explanation:
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Answer:
Area of Parallelogram ABCD=2×ar△ABC
ar△ABC=
s(s−a)(s−b)(s−c)
s=
2
a+b+c
=
2
16+10+12
=19cm
ar△ABC=
19(19−16)×(19−10)(19−12)
=
169×3×9×7
=59.9cm
2
∴ area of parallelogram ABCD=2×59.9=119.8cm
2
Now, area of parallelogram ABCD=base X height
119.8=10×h⇒h=11.98cm
∴ Distance between the shortest sides is 11.98cm
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