Question

dash is to be subtracted from a cube _ 6 to get a square _2a+1​

Answer 1

$Let \: p(x) = a^{3} - 6 \\and \: g(x) = a^{2} - 2a + 1$

$Let \: R\: should \: be \: subtracted \: from \\p(x) \: to \: get \: g(x)$

$\implies p(x) - R = g(x)$

$\implies R = p(x) - g(x)$

$= a^{3} - 6 - (a^{2} - 2a + 1) \\= a^{3} - 6 - a^{2} + 2a - 1 \\= a^{3} - a^{2} + 2a - 7$

Therefore.,

$\underline { \green {a^{3} - a^{2} + 2a - 7}} \:should \: be \\ subtracted \: from \\p(x) \: to \: get \: g(x)$

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