Data on the blood cholesterol levels of 6 rats give mean = 85, s= 12. A 95% confidence interval for the mean blood cholesterol of rats under this condition is
(a)72.4 to 97.6
(b)73.0 to 97.0
(c)75.4 to 94.6
(d)72.4 to 94.6
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The equation of this would be
true \ mean=mean \ +/- \ z\frac{s}{ \sqrt{n} }
The z-value for a 95% confidence level is equal to 1.96.
Then the lower limit would be:
85-1.96 \frac{12}{ \sqrt{6} }=75.398
And the higher limit would be:
85+1.96 \frac{12}{ \sqrt{6} }=94.60
Therefore, the answer is
c)75.4 to 94.6
The equation of this would be
true \ mean=mean \ +/- \ z\frac{s}{ \sqrt{n} }
The z-value for a 95% confidence level is equal to 1.96.
Then the lower limit would be:
85-1.96 \frac{12}{ \sqrt{6} }=75.398
And the higher limit would be:
85+1.96 \frac{12}{ \sqrt{6} }=94.60
Therefore, the answer is
c)75.4 to 94.6
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