Data
Page 1
Find the value of polynomial
8x3-6x2+2at x=1
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Answer:
8x
3
−6x
2
−2x+1
Now
f(0)=1 and
f(1)=1
Hence
f(0)=f(1).
Applying Rolle's theorem in the interval of [0,1], we get
f
′
(c)=0 where cϵ[0,1].
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