Question

DATE 2 PAGE NO.: Find the perimeter of rhombous, the lengths of whose diagonals are 16 and 30 cm ​

Answer 1

Answer:

the perimeter of the rombus=2root d1+d2

=2root16+30=2root46

Answer 2

Answer:

QUESTION:- Find the perimeter of rhombous, the lengths of whose diagonals are 16 and 30 cm

ANSWER:-

GIVEN:- Diagonals AC= 30 cm and DB= 16 cm

Since the diagonals of a rhombus bisect at right angle to each other

Therefore,

$OD = \frac{DB}{2 } = \frac{16}{2} = 8cm$

And,

$OC = \frac{AC}{2} = \frac{30}{2} = 15cm$

Now in right - angled triangle DOC

${ DC}^{2} = {OD}^{2} + {OC}^{2}$

${DC}^{2} = {8}^{2} + {15}^{2}$

$DC {}^{2} = 64 + 225$

${DC}^{2} = 289$

$DC = \sqrt{289}$

$DC = 17$

So, DC = 17cm

So, Now the perimeter = 4× side (as the sides of the rhombus are equal)

= 4×17

= 68 cm

Therefore, the perimeter of the rhombus is 68 cm

HOPE IT HELPS ✌