Question

Date: 2020-11-23 Subject: Class
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Question 1:
If the sum of the squares of the roots x + px - 3 = 0 is 10, then the value of 'p' is

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Answer 1

Answer:

Let the roots of the given equation be a and b.

Let the roots of the given equation be a and b.Then,

Let the roots of the given equation be a and b.Then,Given a

Let the roots of the given equation be a and b.Then,Given a 2

Let the roots of the given equation be a and b.Then,Given a 2 +b

Let the roots of the given equation be a and b.Then,Given a 2 +b 2

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a 2

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a 2 +b

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a 2 +b 2

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a 2 +b 2 =(a+b)

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a 2 +b 2 =(a+b) 2

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a 2 +b 2 =(a+b) 2 −2ab

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a 2 +b 2 =(a+b) 2 −2ab⇒10=(−p)

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a 2 +b 2 =(a+b) 2 −2ab⇒10=(−p) 2

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a 2 +b 2 =(a+b) 2 −2ab⇒10=(−p) 2 −2(−3)

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a 2 +b 2 =(a+b) 2 −2ab⇒10=(−p) 2 −2(−3) [Using (1), (2) and (3)]

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a 2 +b 2 =(a+b) 2 −2ab⇒10=(−p) 2 −2(−3) [Using (1), (2) and (3)]⇒10=p

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a 2 +b 2 =(a+b) 2 −2ab⇒10=(−p) 2 −2(−3) [Using (1), (2) and (3)]⇒10=p 2

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a 2 +b 2 =(a+b) 2 −2ab⇒10=(−p) 2 −2(−3) [Using (1), (2) and (3)]⇒10=p 2 +6

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a 2 +b 2 =(a+b) 2 −2ab⇒10=(−p) 2 −2(−3) [Using (1), (2) and (3)]⇒10=p 2 +6⇒p

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a 2 +b 2 =(a+b) 2 −2ab⇒10=(−p) 2 −2(−3) [Using (1), (2) and (3)]⇒10=p 2 +6⇒p 2

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a 2 +b 2 =(a+b) 2 −2ab⇒10=(−p) 2 −2(−3) [Using (1), (2) and (3)]⇒10=p 2 +6⇒p 2 =4

Let the roots of the given equation be a and b.Then,Given a 2 +b 2 =10......(1)Sum of the roots ⇒a+b=−p......(2)Product of the roots ⇒ab=−3......(3)We know that,a 2 +b 2 =(a+b) 2 −2ab⇒10=(−p) 2 −2(−3) [Using (1), (2) and (3)]⇒10=p 2 +6⇒p 2 =4⇒p=±2