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5) Construct A ABC such that angle B= 100*
BC = 6:4 cm angle c= Soº
and construct
its in circle.
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(i)Drawn BC = 6.4 cm
(ii)∠B=100
∘
and ∠C=50
∘
using the protector. Where the rays YB and XC meet, name the point as A
△ABC is thus obtained
(iii) Construct the angle bisectors of∠B and ∠C and let them meet at point O.
(iv) Through point O, draw a perpendicular to line. Let the perpendicular meet the line at point P.
(v) With O as centre and OP as radius , draw a circle inside the △ABC.
This is the required incircle.
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