Math, asked by barisshaikh66, 4 months ago

DATE
5) Construct A ABC such that angle B= 100*
BC = 6:4 cm angle c= Soº
and construct
its in circle.​

Answers

Answered by Anonymous
1

ANSWER

(i)Drawn BC = 6.4 cm

(ii)∠B=100

and ∠C=50

using the protector. Where the rays YB and XC meet, name the point as A

△ABC is thus obtained

(iii) Construct the angle bisectors of∠B and ∠C and let them meet at point O.

(iv) Through point O, draw a perpendicular to line. Let the perpendicular meet the line at point P.

(v) With O as centre and OP as radius , draw a circle inside the △ABC.

This is the required incircle.

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