Question

Date:
An object of higher 2cm is placed
lon front of a concave
of radius
of cunvature 24cm
Find te position of image
by
drowning
is the image magnification
?​

Answer 1

Answer:

Focal length f=R/2=24/2=−12cm, using sign convention for concave mirror

Object distance u=−4cm

Image distance v=?

An object 2cm high is placed 10cm in front of mirror. What type of mirror, and a radius of what curvature is needed for an upright image that is 4cm high?

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u = 10 cm

h (height of Object) = 2 cm

magnification = Height of Image / Height of Object = 4 / 2 = 2

magnification can also be denoted as; Distance of Image (v) / Distance of Object (u). Which in this case is 2.

| v | / | u | = 2 [I am using modulus as I am still to conclude if image is real or imaginary]

| v | = 20 cm

v = - 20 cm as it is said in question that the image is upright.

(1/v) + (1/u) = (1/f)

f = (u * v) / (u + v) = -20 * 10 / (-20+10) = 20

so focal length of mirror is 20 cm (positive denotes concave mirror)

Explanation:

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