Question

Date chemistry caloulate the wavenumber and wavelength of the third in the bracket series of hydrogen spectrum






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Answer 1

$−−−−=R[n121−n221]m−1=10.97×106(121−221)m−1=410.97×106×3m−1.</p><p></p><p>$

=8.2275×106m−1 

Wave number v−=8.2275×10m−1

Wavelength λ=8.2275×1061m=121.5×10−9m=121.5nm