Question

Date:
EXPT NAME:
NO.
12 Three equally charged small slied are placed as shown
in figure, The object A exerts an dedric force on
object ß equal to 30x10 N
2cm
What electric force does exert on B ?
2 What is the net electric foul on B?​

Answer 1

Given that,

Force $F_{A}= 3.0\times10^{-6}\ N$

Distance between A and B = 2 cm

Distance between B and C = 1 cm

According to figure,

We need to calculate the charge

Using formula of force

$F_{A}=\dfrac{kq^2}{r^2}$

Put the value into the formula

$3\times10^{-6}=\dfrac{kq^2}{2^2}$

$12\times10^{-6}=kq^2$

We need to calculate the electric force C exert on B

Using formula of force

$F_{B}=\dfrac{kq^2}{r^2}$

$F_{B}=\dfrac{12\times10^{-6}}{1^2}$

$F_{B}=12\times10^{-6}\ N$

The direction of force is along BA.

We need to calculate the net electric force on B

Using formula of net force

$F_{net}=F_{B}-F_{A}$

Put the value into the

$F_{net}= (12-3)\times10^{-6}\ N$

$F_{net}=9\times10^{-6}\ N$

Hence, (I). The electric force C exert on B  is $12\times10^{-6}\ N$ along BA

(II). The net electric force on B is $9\times10^{-6}\ N$