Question

Date:
Find the compound Interest of ₹ 16000 at 10%
for 3 ÷2 years. Interest is compounded
half yearly.​

Answer 1

$solution. \\ here \: \\ principal = 16000 \\ rate = 10\% \:per \: annum \\ \: = 5 \% \: per \: half - yer. \\ time = \frac{3}{2} years = 3 \: half-years. \\ amount = (16000 \times (1 + \frac{5}{100} ) {}^{3} \\ = (16000 \times ( \frac{100 + 5}{100} ) {}^{3} \\ = (16000 \times ( \frac{105}{100} )^{3} \\ = (16000 \times (\frac{21}{20}) {}^{ 3} \\ = (16000 \times \frac{21 \times 21 \times 21}{20 \times 20 \times 20} ) \\ = (16 000\times \frac{9261}{8000} ) \\ = (2 \times 9261) \\ =1852 2 \\ compound \: interest = (amount - principal) \\ = (18522 - 16000) = 2522. \: \: answer...$