Math, asked by pss291184, 19 days ago

Date/ Find the value os the unknown exterior angle in the following figure 40° 60° and x

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Answered by anujsethu852
1

Answer:

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Answered by neevenraj30
0

Answer:

Q1) Find the value of the unknown exterior angle x in the following diagrams:

Solution 1:

(i) \angle A\ +\ \angle B+\ \angle C\ =\ 180\degree∠A + ∠B+ ∠C = 180° { angle sum property of triangle }

70\degree+\ 50\degree+\ \angle B\ =\ 180\degree70°+ 50°+ ∠B = 180°

\angle B\ =\ 180\degree-\ 120\degree∠B = 180°− 120°

\angle B\ =\ 60\degree∠B = 60°

(ii) \angle BAC\ +\angle ACB\ =\ x\∠BAC +∠ACB = x {an exterior angle of a triangle is equal to the sum of the opposite interior angle }

65\degree+45\degree=x65°+45°=x

110\degree=x110°=x

(iii) \angle CAB+\angle ABC\ =\ x∠CAB+∠ABC = x {an exterior angle of a triangle is equal to the sum of the opposite interior angle }

30\degree+40\degree\ =\ x\30°+40° = x

70\degree=x70°=x

(iv) \angle BCA+\angle CBA\ =\ x∠BCA+∠CBA = x {an exterior angle of a triangle is equal to the sum of the opposite interior angle }

60\degree+60\degree\ =\ x60°+60° = x

120\degree=x120°=x

(v) \angle A+\angle B=\ x∠A+∠B= x {an exterior angle of a triangle is equal to the sum of the opposite interior angle }

50\degree+50\degree=\ x50°+50°= x

100\degree=\ x\100°= x

(vi) \angle A+\angle B\ =\ x\∠A+∠B = x {an exterior angle of a triangle is equal to the sum of the opposite interior angle }

30\degree+60\degree\ =\ x\30°+60° = x

90\degree=\ x90°= x

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