Physics, asked by shikhagaur2020, 1 month ago

Date - I9.04.2021
QU
An object is dropped from the top of
the building with the constant
acceleration of 5m/ sec² find
velocity
after 5 see it was drop.

Answers

Answered by Pratik010408

1

Answer:

Velocity = acceleration×time

a = 5m/s, t = 5s

hence V = 5m/s × 5s = 25m/s or 25m s^-2

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