Question

Date
Page
ܩ
A
stone Projected so as to reach a height
14 ho passes through x andy with velocities
~/4 and vis. The distance between the
Points is
3 Gm
o8m
216m
a sm​

Answer 1

Explanation:

In travelling from p to q the stone looses its velocity from u/2 to u/3. So, v2=u2−2gh

⇒(u3)2=(u2)2−2gh

⇒536u2=2gh

⇒u22g=365h

Maximum height achieved by the stone hmax=u22g=

MARK me as brainliest

and God bless you

stay home stay safe mark me brainliest