Question

Date
Page
Abody of mass 2kg travels according
the law X(t) =pt+qt^2+rt^3 , where
P=3 m/s , q= 4 m/s^2 and r = 5 m/s^-3
The force acting on the body at t =2s is
136N
134N
158 N
68N​

Answer 1

Answer:

136N

Explanation:

given function is a displacement function which can be identified by units given for p, q, r. so differentiate x(t)twice which gives the exoression 2q+(3*2*r*t)

and substitute q, r, t values results to 68m/s^2

given mass =2kg

force =mass *acceleration

=2*68=136