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Find 3 consicutive odd numbers whose sum is 147
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Answer:
The required 3 consecutive odd numbers are 47, 49, 51.
Step-by-step-explanation:
Let the first odd number be ( x - 2 ).
The second consecutive odd number = ( x - 2 + 2 )
The third consecutive odd number = ( x - 2 + 2 + 2 )
From the given condition,
The sum of 3 consecutive odd numbers is 147.
( x - 2 ) + ( x - 2 + 2 ) + ( x - 2 + 2 + 2 ) = 147
⇒ x - 2 + x + x + 2 = 147
⇒ x + 2x - 2 + 2 = 147
⇒ 3x + 0 = 147
⇒ 3x = 147
⇒ x = 147 ÷ 3
⇒ x = 49
∴ The second odd number = 49
Now,
The first odd number = ( x - 2 ) = ( 49 - 2 ) = 47
And,
The third odd number = ( x + 2 ) = ( 49 + 2 ) = 51
∴ The required 3 consecutive odd numbers are 47, 49, 51.
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