Date: Page No. ) The sum of fiest'n teens of in terms of an out hermetic brogression is given by the formula. So =sn= 3n²+ n then it 3 term
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Explanation :
In the AP, Sn = 3n^2+2n.
S1 = a = 3+2 = 5
S2 = a+a+d = 3*2^2 + 2*2 = 12+4 = 16
2a+d = 16, or
d = 16–2a = 16–10 = 6.
So, the third term of the AP = a + 2d = 5+12 = 17. Answer.
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