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Which of the following number is the greatest √2,3√3,4√4,6√6 ?
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Step-by-step explanation:
LCM of 2,3,4 and 6 is 12 so sqrt2 is 2^1/2 or 2^6/12 or (2^6)^1/12 which is 64^1/12
cube root 3 is 3^1/3 or 3^4/12 or (3^4)^1/12 which is 81^1/12
12 root of 81 is greater than 12 root of 62 and the pattern continues so the largst number is 6 root of 6
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