Physics, asked by srideviguttedar9774, 4 days ago

Date: Q. Find the value of acceleration due to gravity a 9) at a height 3200km above the surface of the earth and b At depth 8 km leelow the surface of earth. Radius of eauth=6400km and acceleration due the surface of earth = 9.8m/s

Answers

Answered by kk0838994
0

Explanation:

The acceleration due to gravity varies with height as

g=g((R+h)2R2)

By substituting the values in the above given equation we get

g=9.8((6.4×106+3.2×106)2(6.4×106)2)

On solving the above equation we get the value of acceleration due to gravity at height of 3200km

g=4.4m/s2

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