Math, asked by shaikanas2219, 6 months ago

DATE
sin^2 82 1 /2 - sin²22
1/2°​

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Answered by Anonymous
7

 \therefore \rm \sin^{2} 82 \frac{1}{2}  -   \sin^{2}22 \frac{1}{2} \degree \\  \implies \rm  { \sin }^2 41 \degree -  { \sin}^{2} 11\degree \\ \implies \rm ({\frac{1}{\sqrt{2}}})^2 - ({\frac{1}{4}})^{2} \\ \implies \rm \frac{1}{2} - \frac{1}{16} \\ \implies \rm \bf \frac{-8}{16}

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