Question

Date:
to produce
sogm,
How many coulombs are required to produce 50gm
of Al when electrode reaction is
Al power++ + 3epower- Al (Atomic mass of Al=27)
Solutions​

Answer 1

Explanation:

According to equation 1 mole of Al i.e 27 grams of Al is deposited by 3 Faraday electricity

So 90 grams of Al is deposited by

27

90×3×96500

=9650000

which can be written as 9.65×10

6

solution