Question

DATE.
wire having resistance R
to reduced
A
given
wire ha
streched so
to half the
diameter of pervious
Value what will be
new
resistance​

Answer 1

Answer:

R is inversely promotional to cross section area of wire here we reduce the wire diameter and another value are same R= resistivity×L/A , R=rho×L/πR^2 butif for this qs R1/R2= A1^2/A2^2 here for first d1= d then d2 = d/2 ,R1=R , R/R2=( d/2(^4/d^4 , R/R2= d^4/16d^4 then R2=16R