Question

Datermine the current in each branch of the network shown in the figure​

Answer 1

Explanation:

Current flowing through various branches of the circuit is represented in the given figure. I1 = Current flowing through the outer circuit I2 = Current flowing through branch AB I3 = Current flowing through branch AD I2 − I4 = Current flowing through branch BC I3 + I4 = Current flowing through branch CD I4 = Current flowing through branch BD For the closed circuit ABDA, potential is zero i.e., 10I2 + 5I4 − 5I3 = 0 2I2 + I4 −I3 = 0 I3 = 2I2 + I4 … (1) For the closed circuit BCDB, potential is zero i.e., 5(I2 − I4) − 10(I3 + I4) − 5I4 = 0 5I2 + 5I4 − 10I3 − 10I4 − 5I4 = 0 5I2 − 10I3 − 20I4 = 0 I2 = 2I3 + 4I4 … (2) Read more on Sarthaks.com - https://www.sarthaks.com/18325/determine-the-current-in-each-branch-of-the-network-shown-in-figure